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42=3w^2-11w
We move all terms to the left:
42-(3w^2-11w)=0
We get rid of parentheses
-3w^2+11w+42=0
a = -3; b = 11; c = +42;
Δ = b2-4ac
Δ = 112-4·(-3)·42
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-25}{2*-3}=\frac{-36}{-6} =+6 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+25}{2*-3}=\frac{14}{-6} =-2+1/3 $
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